C°=........ R°=......... F°=230° tlong jwb kak
Matematika
andika846
Pertanyaan
C°=........ R°=......... F°=230° tlong jwb kak
2 Jawaban
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1. Jawaban rendyyaqin220603
tC = 5/9 × (tF – 32)
tC = 5/9 × (230 – 32)
tC = 5/9 × (198)
tC = 110
tR = 4/9 × (tF – 32)
tR = 4/9 × (230 – 32)
tR = 4/9 × (198)
tR= 88
jadi, C° = 110° = R° = 88° = F = 230° -
2. Jawaban Kuchuz
(230-32) x 5/9 = 110°C
(230-32) x 4/9 = 88°R