minta bantuannya yaaaa,dikumpulin besok

1. lim x→-3 3x+5/2x
=3(-3)+5/2(-3)
=(-9)+5/(-6)
= -4/-6
= 2/3

2. lim x→-1 3x²+5/x
=3 (-1)²+5/(-1)
=3+5/(-1)
= 8/-1
= -8

3. lim x→3 x²-5x+6/x-3
= (3)²-5.3+6/3-3
= 9-15+6/0
= 0/0
karena 0/0 harus menggunakan faktor
[tex] = \frac{ {x}^{2} - 5x + 6 }{x - 3} \\ = \frac{(x - 3)(x - 2)}{x - 3 } \\ = x - 2 \\ = 3 - 2 = 1[/tex]