jika log2=0,301 dan log6=0,778, nilai log48 adalah? *dikasih keterangan

Log 48 = log (6 x 8)
= log 6 + log 8
= 0,778 + 0,301
= 1,079

dik: log2= 0,301
log 6=0,778

log48=log(2×2×2×6)
log48=log2+log2+log2+log6
log48=3×log2+log6
log48=3×0,301+0,778
log48=0,903+0,778
log48=1,681