[tex]3 \sqrt{50 } - 2 \sqrt{18} + \sqrt{98} [/tex]
Matematika
shinta650
Pertanyaan
[tex]3 \sqrt{50 } - 2 \sqrt{18} + \sqrt{98} [/tex]
2 Jawaban
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1. Jawaban zakipelajar
Mapel : Matematika
Bab : Akar
[tex]3 \sqrt{50} - 2 \sqrt{18} + \sqrt{98} [/tex]
[tex] = 3 \sqrt{25 \times 2} - 2 \sqrt{9 \times 2} + \sqrt{49 \times 2} [/tex]
[tex] = 3 \times 5 \sqrt{2} - 2 \times 3 \sqrt{2} + 7 \sqrt{2} [/tex]
[tex] = 15 \sqrt{2} - 6 \sqrt{2} + 7 \sqrt{2} [/tex]
[tex] = 16 \sqrt{2} [/tex] -
2. Jawaban ferlitajihan
Pembahasan :
[tex]3 \sqrt{50 } - 2 \sqrt{18} + \sqrt{98} \: \\ = 3 \sqrt{25 \times 2} -2 \sqrt{9 \times 2} + \sqrt{49 \times 2} \\ = 15 \sqrt{2} - 6 \sqrt{2} + 7 \sqrt{2} \\ = (15 - 6 + 7) \sqrt{2} \\ = 16 \sqrt{2} \: [/tex]
Good Luck ^^