Matematika

Pertanyaan


[tex]3 \sqrt{50 } - 2 \sqrt{18} + \sqrt{98} [/tex]

2 Jawaban

  • Mapel : Matematika
    Bab : Akar

    [tex]3 \sqrt{50} - 2 \sqrt{18} + \sqrt{98} [/tex]
    [tex] = 3 \sqrt{25 \times 2} - 2 \sqrt{9 \times 2} + \sqrt{49 \times 2} [/tex]
    [tex] = 3 \times 5 \sqrt{2} - 2 \times 3 \sqrt{2} + 7 \sqrt{2} [/tex]
    [tex] = 15 \sqrt{2} - 6 \sqrt{2} + 7 \sqrt{2} [/tex]
    [tex] = 16 \sqrt{2} [/tex]
  • Pembahasan :

    [tex]3 \sqrt{50 } - 2 \sqrt{18} + \sqrt{98} \: \\ = 3 \sqrt{25 \times 2} -2 \sqrt{9 \times 2} + \sqrt{49 \times 2} \\ = 15 \sqrt{2} - 6 \sqrt{2} + 7 \sqrt{2} \\ = (15 - 6 + 7) \sqrt{2} \\ = 16 \sqrt{2} \: [/tex]

    Good Luck ^^

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