Matematika

Pertanyaan

2log3 dikali 4log8 dikali 3log16=

1 Jawaban

  • 2log 3 × 4 log8 × 3log 16
    [tex] = 2 log(3) \times 4 log( {2}^{3} ) \times 3 log( {4}^{2} ) [/tex]
    =3×2
    =6

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