2log3 dikali 4log8 dikali 3log16=
Matematika
sintaavrilia
Pertanyaan
2log3 dikali 4log8 dikali 3log16=
1 Jawaban
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1. Jawaban Cinderea
2log 3 × 4 log8 × 3log 16
[tex] = 2 log(3) \times 4 log( {2}^{3} ) \times 3 log( {4}^{2} ) [/tex]
=3×2
=6