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1 Jawaban

  • 2(sinx.cos(2x))/(cosx.sin(2x)) - 5tanx + 5 = 0
    2(tanx.cotan(2x)) - 5tanx + 5 = 0
    2tanx.(1/tan(2x)) - 5tanx + 5 = 0
    2tanx/(tan(2x)) - 5tanx + 5 = 0
    2tanx/(2tanx/(1 - tan²x)) - 5tanx + 5 = 0
    2tanx(1 - tan²x)/(2tanx) - 5tanx + 5 = 0
    1 - tan²x - 5tanx + 5 = 0
    -tan²x - 5tanx + 6 = 0
    tan²x + 5tanx - 6 = 0

    (tanx + 6)(tanx - 1) = 0

    tan(x1) = -6, tan(x2) = 1

    tan(x1 + x2) = (tan(x1) + tan(x2))/(1 - tan(x1)tan(x2))
    = (-6 + 1)/(1 - (-6)(1))
    = -5/(1 + 6)
    = -5/7