B. Indonesia

Pertanyaan

persamaan kuadrat? (6,0) (2,0) (0,5)

1 Jawaban

  • f (x) = ax² + bx + c

    maka,

    f (6) = 0
    a(6)² + b(6) + c = 0
    36a + 6b + c = 0
    c = -36a - 6b

    f (2) = 0
    a(2)² + b(2) + c = 0
    4a + 2b + c = 0
    4a + 2b - 36a - 6b = 0
    -32a - 4b = 0
    -4b = 32a
    4b = -32a
    b = -32/4 a
    b = -8a

    f (1) = 5
    a(1)² + b(1) + c = 5
    a + b + c = 5
    a - 8a - 36a - 6b = 5
    -43a - 6(-8a) = 5
    -43a + 48a = 5
    5a = 5
    a = 5/5
    a = 1

    b = -8a
    b = -8(1)
    b = -8

    c = -36a - 6b
    c = -36(1) - 6(-8)
    c = -36 + 48
    c = 12

    f (x) = ax² + bx + c
    f (x) = x² - 8x + 12
    y = x² - 8x + 12

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