Matematika

Pertanyaan

tolong dijawab yaaa...
tolong dijawab yaaa...

2 Jawaban

  • Pembahasan :
    [tex] = \sqrt[2]{ {13}^{2} - {5}^{2} } \\ = \sqrt[2]{169 - 25} \\ = \sqrt[2]{144} = 12 = 6 [/tex]

    Panjang EC
    [tex] = \sqrt[2]{ {6}^{2} + {8}^{2} } \\ = \sqrt[2]{36 - 64} \\ = \sqrt[2]{100} = 10[/tex]
    Opsi B

    Maaf kalau salah :(
  • BD^2 = AB^2 - AD^2
    BD^2 = 13^2 - 5^2.
    BD^2 = 169 - 25
    BD^2 = 144
    BD = V144 = 12
    DC = 1/2 x BD
    DC = 1/2 x 12 = 6
    EC^2 = ED^2 + DC^2.
    EC^2 = 8^2 + 6^2
    EC^2 = 64 +36
    EC^2 = 100
    EC = V100
    EC = 10 cm