Matematika

Pertanyaan

Jika f (x) =x^5+mx^4+2x^3+x+1 dan f (2) =3, mama nilai f(-2) =

1 Jawaban

  • f (x) = x^5+mx^4+2x^3+x+1

    f (2) = 2^5+m(2)^4+2(2)^3 + (2) + 1 = 3
    3 = 32 + 16m + 16 + 3
    16m = -48
    m = -3

    Maka, nilai f(-2)
    f (-2) =(-2)^5 + (-3)(-2)^4 + 2(-2)^3 + (-2) + 1
    = -32 - 48 - 8 - 2 + 1
    = -89

Pertanyaan Lainnya