Tentukan luas daerah arsiran pada bangun berikut.

Mapel: Matematika
Bab : Bangun Datar

A)

s = 14 cm
d = 14 cm
r = 7 cm

L1 = s × s
L1 = 14 × 14
L1 = 196 cm^2

L2 = 1/2 × 22/7 × r^2
L2 = 1/2 × 22/7 × 7 × 7
L2 = 77 cm^2

L arsir = L2 - L1
L arsir = 196 - 77
L arsir = 119 cm^2

B)

s = 10 cm
d = 10 cm
r = 5 cm

L1 = s.s
L1 = 10 × 10
L1 = 100 cm^2

L2 = 3,14 × r^2
L2 = 3,14 × 5 × 5
L2 = 78,5 cm^2

L arsir = L2 - L1
L arsir = 100 - 78,5
L arsir = 21,5 cm^2

a. (1) L = s x s
= 14cm x 14 cm
= 196 cm²
(2) L = 1/2 x π x r²
= 1/2 x 22/7 x 7 x 7
= 11 x 7
= 77 cm ²
L yg diarsir = L1-L2
= 196cm²-77cm²
= 99 cm²
b. (1) L = s x s
= 10cm x 10cm
= 100cm²
(2) L = π x r²
= 3,14 x 5cm x 5cm
= 78,5cm²
L yg diarsir = L1-L2
= 100cm²-78,5cm²
=21,5cm²