Matematika

Pertanyaan

Jika f (x) =x^5+mx^4-2x^3+x+1 dan f(2) =3, mama nilai f(-2) =

1 Jawaban

  • [tex]f (x) =x^5+mx^4-2x^3+x+1 \\ f (2) = 2^5 + m\times2^4 - 2\times2^3 + 2 +1\\ 3 = 32 + 16m - 16 + 3 \\ m = -1 f (x) = x^5-x^4-2x^3+x+1 \\ f(-2)= (-2)^5 - (-2)^4 - 2(-2)^3 + (-2) + 1 \\ f(-2)= -32 - 16 + 16 - 2 +1 \\ f(-2)= -33[/tex]

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