(x^-4.y^3.z^0)^3 dibagi 2^4.y^-5

[tex] {( {x}^{ - 4} . {y}^{3}. {z}^{0}) }^{3} \div {2}^{4} . {y}^{ - 5 } \\ = \frac{ {x}^{ - 12}. {y}^{9 - ( - 5)} . {z}^{0} }{16} \\ = \frac{ {x}^{ - 12} . {y}^{14} .1}{ 16} \\ = \frac{ {y}^{14} }{16 {x}^{12} } [/tex]