Matematika

Pertanyaan

ika f(x) = akar pangkat 3 (2x^3 + 3x + 3)^2, nilai f'(1) =

1 Jawaban

  • jika f(x) =
    [tex] \sqrt[3] {({ {2x}^{3} } + 3x + 3)}^{2} [/tex]
    maka f' (1) =
    [tex] \sqrt[3] {({ {2.1}^{3} } + 3.1+ 3)}^{2} [/tex]
    [tex] \sqrt[3] {({ {2.1}^{3} } + 3.1 + 3)}^{2} \\ = \sqrt[3]{ {(2 + 3 + 3)}^{2 } } \\ = \sqrt[3]{ {8}^{2} } \\ = \sqrt[3]{64} \\ = 4[/tex]

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