Diketahui f(x)=x+6 dan (gof) (x) =x²+10x+27. Rumus fungsi g(x+1) .... a. x²-2 b. x²+2 c. x²+2x+3 d. x²+10x+27 e. x²+10x+30 tolong dijawab ya

(gof)(x) = x^2 + 10x + 27
G (f(x)) = x^2 + 10x + 27
G(x+6) = x^2 +10x + 27
Misal x+6 = p
x = p-6
G(p) = (p-6)^2 + 10(p-6) +27
= (p^2 -12p + 36) + 10p -60 + 27
= p^2 -2p + 3

G(x) = x^2 -2x + 3

G(x+1) = (x+1)^2 -2(x+1) + 3
= x^2 + 2x + 1 -2x -2 + 3
= x^2 + 2

Jawabannya B