Diketahui f(x) = 2x-1 dan g(x) = 3x+4. Jika h(x) =(fxg) (x), rumus fungsi h(x-1) tolong dijawab ya

jawab

h(x) = f(x) . g(x)
h(x)=  (2x -1)(3x +4)
h(x-1) = (2(x- 1) - 1)) (3(x -1) + 4))
h(x-1)= (2x -2 -1)(2x - 3 +4)
h(x-1) = (2x -3)(2x +1) = 4x² - 2x - 3