Matematika

Pertanyaan

bentuk sederhana dari akar 98 + akar 72 - akar 50 + akar 8

2 Jawaban

  • √98 + √72 - √50 + √8
    = √49×2 + √36×2 - √25×2 + √4×2
    = 7√2 + 6√2 - 5√2 + 2√2
    = (7+6-5+2)√2
    = 10√2

  • [tex] \sqrt{98} + \sqrt{72} - \sqrt{50} + \sqrt{8} \\ = \sqrt{2 \times 49} + \sqrt{2 \times 36} - \sqrt{2 \times 25} + \sqrt{2 \times 4} \\ = 7 \sqrt{2} + 6 \sqrt{2} - 5 \sqrt{2} + 2 \sqrt{2} \\ = \sqrt{2} (7 + 6 - 5 + 2) \\ = \sqrt{2} (10) \\ = 10 \sqrt{2} [/tex]

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