Matematika

Pertanyaan

19. Jika titik A (4,2,q), B(2,-2,1), dan C(8,p+2,-8) segaris, nilai p+q=....
a. 10 d. -6
b. 8 e. -10
c. 6

beserta caranya!

1 Jawaban

  • Jika titik A (4,2,q), B(2,-2,1), dan C(8,p+2,-8) segaris

    Segaris maka
    AB = k AC

    k = koefisien

    AB = b - a = (2, -2, 1) - (4, 2, q) = (-2, -4, 1 - q)
    AC = c - a = (8, p + 2, -8) - (4, 2, q) = (4, p, -8 - q)

    AB = k AC
    (-2, -4, 1 - q) = k (4, p, -8 - q)

    -2 = 4k
    k = -½

    -4 = kp
    -4 = (-½) p
    p = -2 × -4 = 8

    1 - q = k (-8 - q)
    1 - q = -½ (-8 - q)
    -2 (1 - q) = - 8 - q
    -2 + 2q = -8 - q
    2q + q = -8 + 2
    3q = -6
    q = -2

    p + q = 8 + (-2) = 6

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