Diketahui f(x) = x² + 2x – 5 dan g(x) = x + 3 tentukan (fog) (2)

fog(x) = (x+3)^2+2(x+3)-5
fog(2) = (2+3)^2+2(2+3)-5
= 5^2+2(5)-5
= 25+10-5 = 30

fog (2) = g(x² + 2x – 5)(2)
= g(2² + 2.2– 5)
= g(3)
fog= x+3
= 3+3
=6