Matematika

Pertanyaan

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1 Jawaban

  • a. Lebar^2 = Diagonal^2 - Panjang^2
    L^2 = 25^2 - 15^2
    L^2 = 625 - 225
    L^2 = 400
    [tex]l = \sqrt{400} \\ l = 20 \: cm[/tex]
    Keliling persegi panjang
    = 2(p + l)
    = 2(25 cm + 20 cm)
    = 2(45 cm)
    = 90 cm

    Luas persegi panjang
    = p × l
    = 25 cm × 20 cm
    = 500 cm^2

    b. Jika x = sisi persegi

    Maka,
    Diagonal^2 = x^2 + x^2
    [tex] {10 \sqrt{2} }^{2} =2 {x}^{2} \\ 100 \times 2 = 2{x}^{2} \\ 100 = {x}^{2} \\ x = \sqrt{100} \\ x = 10 \: cm[/tex]

    Luas persegi
    = sisi × sisi
    = x × x
    = 10 cm × 10 cm
    = 100 cm^2

    Keliling persegi
    = 4 × sisi
    = 4 × x
    = 4 × 10 cm
    = 40 cm