Soal teorema limit lim x=0 2x pangkat 2 -5/3x+1

jawab
limit (x->0)  2x^2 - 5 /(3x + 1)
sub x = 0
limit = -5/1 = - 5

Bab : Limit

Penyelesaian:
lim x = 0   (2x² - 5)/(3x + 1)    | subtitusikan nilai x=0 |
= (2(0)² - 5)/(3(0) + 1)
= (0 - 5)/(0 + 1)
= -5/1
= -5