Akar-akar persamaan kuadrat 2x²- 9x +7=0 adalah

2x² - 9x + 7 = 0
1/2 ( 2x - 2 ) ( 2x - 7 )
1/2 . 2( x - 1 ) ( 2x - 7 )
( x - 1 ) ( 2x - 7 )
x1 = 1 √ x2 = 7/2

HP = { x1 = 1 , x2 = 7/2 }

jawab :

2x²-9x+7 = 0
(2x -7)(x-1) = 0
x=7/2 atau x = 1