tolong jwab nmor 5-11

5) p = 2 (A)
6) -3 ≤ x ≤ ½ (A/B)
7) hasil penjumlahan = 3+2,5 = 5,5 (A)
8) kembalian = 20.000-13.000 = 7.000 (B)
9) astronot di bumi = 600 kg (A)
10) kartu persegi = 17 dan kartu segitiga = 16 (A)
11) (f•g)(2) = 3

5. x1+x2 = -b/a = -(-p/2) = p/2
x1.x2 = c/a = (p-1)/2
x2² + x1² = 0
(x1 + x2)² - 2x1.x2 = 0
p²/4 - 2(p-1)/2 = 0
p²/4 - p + 1 = 0 (kali 4)
p² - 4p + 4 = 0
(p - 2)² = 0
p = 2

6. 2x² + 5x ≤ 3
2x² + 5x - 3 ≤ 0
(2x - 1)(x + 3) ≤ 0
Karena tandanya lebih kecil, maka :
-3≤x≤1/2

7. 2x + 4y = 16 (bagi 2)
x + 2y = 8
x = 8 - 2y
3x - 2y = 4
3(8-2y) - 2y = 4
24 - 8y = 4
-8y = -20
y = 20/8 = 5/2
x = 8 - 2(5/2) = 8 - 5 = 3
x + y = 3 + 5/2 = 3 + 2,5 = 5,5
Semoga membantu, klu semuanya nanti terlalu panjang jadinya.