f(x)=2x,g(x)=2-x2 dan h (x)= x+1,tentukan nilai (hogof)(1) adalah

[tex](h\circ g\circ f)(1) = h(g(f(1))) \\ (h\circ g\circ f)(1) = h(g(2(1))) \\ (h\circ g\circ f)(1) = h(g(2)) \\ (h\circ g\circ f)(1) = h(2-2^2) \\ (h\circ g\circ f)(1) = h(2-4) \\ (h\circ g\circ f)(1) = h(-2) \\ (h\circ g\circ f)(1) = -2+1 \\ (h\circ g\circ f)(1) = -1[/tex]

=h o g {f(x)}
=h o g {f(2x)}
=h{g(2-(2x)2)}
=2-4x2+1
=-4x2 + 3