Diketahui F : R-> R, g:R -> g(x)=2×+3 dan (fog) (x)=(2×2+32×+26 Rumus f(×)=.......

g(x) = 2x + 3

Misalkan :
y = 2x + 3
y - 3 = 2x
(y-3)/2 = x

(f o g) (x) = 2x² + 32x + 26
f(2x+3) = 2x² + 32x + 26
f(x) = 2((y-3)/2)² + 32(y-3)/2 + 26
f(x) = 2 (y² - 6y + 9)/4 + 16(y-3) + 26
f(x) = (y² - 6y + 9)/2 + 16y - 48 + 26
f(x) = (x² - 6x + 9)/2 + 16x - 22
f(x) = (x² - 6x + 9 + 32x - 44)/2
f(x) = (x² + 26x - 35)/2