Nilai 5a+b+2c dari sistem persamaan 2a-b-6=0 2b+3c-4=0 3a-c-8=0

Eliminasi B
2a - b - 6 = 0 (dikali 2) 4a - 2b - 12
2b + 3c - 4 = 0 (dikali 1) 2b + 3c - 4
(kedua persamaan dijumlahkan)
4a - 2b + 2b + 3c - 12 - 4 = 0
4a + 3c - 16 = 0

Eliminasi C
4a + 3c - 16 = 0 (dikali 1) 4a + 3c -16 =0
3a - c - 8 = 0 (dikali 3) 9a - 3c - 24 = 0
(kedua persamaan dijumlahkan)
13a - 40 = 0
13a = 40
a = 40/13 >>>>>>>>> nilai a

2a - b - 6 = 0
2(40/13) - b - 6 = 0
80/13 - 6 = b
(80-78)/13 = b
2/13 = b >>>>>>>> nilai b

3a - c - 8 = 0
3(40/13) - c - 8 = 0
(120-104)/13 = c
16/13 = c >>>>>>>>> nilai c

5a+b+2c
= 5(40/13) + 2/13 + 2(16/13)
= (200 + 2 + 32)/13
= 234/13
= 18