Matematika

Pertanyaan

1) pengurangan 2y²-3y+15 dari 3y²+5y-10 2)perkalian (2y-3) (y+2) 3)2x+3y²+4xyz Jika: X=3 Y= -4 Z=2

2 Jawaban

  • 1.)
    [tex]1) (2y {}^{2} - 3y + 15) - 3y {}^{2} + 15y - 10 = - y {}^{2} + 12y + 5[/tex]
  • Dik : X=3 Y= -4 Z=2
    Dit : 1) 3y²+5y-10 - (2y²-3y+15 ) =.....
    2) (2y-3) (y+2) =.....
    3) 2x+3y²+4xyz=.....
    JB : 1) 3y²+5y-10 - {2y²-3y+15 }
    = 3(-4)²+5(-4)-10 - {2(-4)²-3(-4)+15 }
    = 3(16)-20-10 - {2(16)+12+15}
    = 48-10 - {32+27}
    = 38 - 59
    = -21
    2) (2y-3) (y+2)
    = 2y³+4y-3y-6
    = 2y³+y-6
    = 2(-4)³+(-4)-6
    = 2(-64)-4-6
    = -128-10.
    = -138
    3) 2x+3y²+4xyz
    = 2(3)+3(-4)²+4(3)(-4)(2)
    = 6+3(16)+12(-8)
    = 6+48-96
    = 54-96
    = -42

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