Hitunglah ph dari 3 mol asam cuka dalam 500 ml larutan jika ka asam cuka 1,5.10-5

CH3COOH → CH3COO + H

[CH3COOH] = mol x L
= 3 x 500/1000
= 3 x 0,5
= 1,5
= 15 x 10^-1

[H+] = √Ka.Ma
= √1,5 x 10^-5 . 15 x 10^-1
= √22,5 x 10^-6
= 4,7 x 10^-3

pH = -log[H+]
= -log4,7 x 10^-3
= 3 - log4,7

Maaf kalau salah.