Matematika

Pertanyaan

1 . diketahui = f (x) = 2x+1 dan g(x)=3x+5

tentukan a .(fog) x. b. (gof) x

2. diket = f(x)=2x+1. dan g(x)=6x²+4x+7

tentukan = a. (gof). (x) b. (gof). (2).


3. diketahui = f(x) =5x+2
-------
3x-4
tentukan = a . f - ¹ (x). b. f-¹(3)

tolong bantuan nya yaa sobat besok harus kumpul nihhh..

1 Jawaban

  • 1) f (x) = 2x +1 dan g(x) = 3x +5
    a) fog(x) = f { g(x) }
    = f (3x+5)
    = 2(3x +5) +1
    = 6x + 10 + 1
    = 6x +11
    b) gof (x) = g { f (x) }
    = g (2x +1)
    = 3(2x +1) '5
    = 6x +3 +5
    = 6x +8
    2) f (x) = 2x + 1 dan g (x) = 6x^2+ 4x +7
    a) gof (x) = g { f (x) }
    = g (2x+1)
    = 6(2x+1)^2 +4(2x +1) +7
    = 24x^2 + 24x +6 + 8x + 4 +7
    = 24x^2 + 32x +17
    b) gof (2) = 24(2)^2 + 32(2) + 17
    = 96 + 64 + 17
    = 177
    3) f(x) = (5x +2)/(3x -4)
    y = (5x +2)/(3x -4)
    (3x -4)y = 5x +2
    3xy -4y = 5x + 2
    3xy -5x = 4y +2
    (3y -5)x = 4y +2
    x = (4y +2)/(3y -5)
    f-1(x) = (4x +2)/(3x -5)
    b) f-1(3) = (4.3 +2)/(3.3 -5)
    = (12+2)/(9-5)
    = 14/4
    = 7/2
    = 3 1/2

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